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NYT Pips Today: Hints, Answers And Walkthrough For Tuesday, April 21

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Forbes
2026/04/20 - 22:15 501 مشاهدة
InnovationGamingNYT Pips Today: Hints, Answers And Walkthrough For Tuesday, April 21ByErik Kain,Senior Contributor.Forbes contributors publish independent expert analyses and insights. I write about TV shows, movies, video games, entertainment & culture.Follow AuthorApr 20, 2026, 06:15pm EDT--:-- / --:--This voice experience is generated by AI. Learn more.This voice experience is generated by AI. Learn more. Today's PipsCredit: NYTWelcome back, Pipsqueaks. Today’s NYT Pips puzzles are a lot of fun, though once again I found myself struggling with the Medium puzzle more than the Hard puzzle today. I’m curious to know if any of you had a similar experience. Grab some dominos and let’s do this thing!Looking fo Monday’s Pips? Read our guide right here.How To Play PipsIn Pips, you have a grid of multicolored boxes. Each colored area represents a different “condition” that you have to achieve. You have a select number of dominoes that you have to spend filling in the grid. You must use every domino and achieve every condition properly to win. There are Easy, Medium and Difficult tiers.Here’s an example of a difficult tier Pips:Pips exampleScreenshot: Erik KainMORE FOR YOUAs you can see, the grid has a bunch of symbols and numbers with each color. On the far left, the three purple squares must not equal one another (hence the equal sign crossed out). The two pink squares next to that must equal a total of 0. The zig-zagging blue squares all must equal one another. You click on dominoes to rotate them, and will need to since they have to be rotated to fit where they belong. Not shown on this grid are other conditions, such as “less than” or “greater than.” If there are multiple tiles with > or < signs, the total of those tiles must be greater or less than the listed number. It varies by grid. Blank spaces can have anything. The various possible conditions are:= All pips must equal one another in this group.≠ All pips must not equal one another in this group.&...
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